Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 52

Answer

$\frac{30-5\sqrt 3}{33}$

Work Step by Step

$\frac{5}{6+\sqrt 3}=\frac{5(6-\sqrt 3)}{(6+\sqrt 3)(6-\sqrt 3)}=\frac{30-5\sqrt 3}{36-3}=\frac{30-5\sqrt 3}{33}$
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