Answer
$ x=6t+3$ ; $ y=13t-1$
Work Step by Step
For a line, we have: $(3,-1); (9,12)$
$ x_1=3, x_2=9,y_1=-1, y_2=12$
Now, in parametric from:
$ x=(x_2-x_1) t+x_1=6t+3$
and $ y=(y_2-y_1)t_1+y_1 =13t-1$
So, $ x=6t+3$ ; $ y=13t-1$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 9 - Section 9.5 - Parametric Equations - Exercise Set - Page 1020: 52
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