Answer
$ x=4+3 \cos t $ ; $ y=-1+5 \sin t $
Work Step by Step
Standard form of a Ellipse: $\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1$
$ h=4, k=-1; a=3; b=5$
Now, in parametric from:
$ x=h+a \cos t =4+3 \cos t $
and $ y=k+b \sin t =-1+5 \sin t $
So, $ x=4+3 \cos t $ ; $ y=-1+5 \sin t $
