Answer
a) The resultanat sum of matrices is $A+B=\left[ \begin{array}{*{35}{l}}
3 & 2 \\
6 & 2 \\
5 & 7 \\
\end{array} \right]$
B) The resultanat difference of matrices is $A-B=\left[ \begin{array}{*{35}{l}}
-1 & 4 \\
0 & 6 \\
5 & 5 \\
\end{array} \right]$
c) The resultant matrix is $\left( -4 \right)A=\left[ \begin{array}{*{35}{l}}
-4 & -12 \\
-12 & -16 \\
-20 & -24 \\
\end{array} \right]$
d)The resultant matrix is $3A+2B=\left[ \begin{array}{*{35}{l}}
7 & 7 \\
15 & 8 \\
15 & 20 \\
\end{array} \right]$
Work Step by Step
(a)
Perform the addition of the matrices $A$ and $B$ as below:
$\begin{align}
& A+B=\left[ \begin{array}{*{35}{l}}
1 & 3 \\
3 & 4 \\
5 & 6 \\
\end{array} \right]+\left[ \begin{array}{*{35}{l}}
2 & -1 \\
3 & -2 \\
0 & 1 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
1+2 & 3-1 \\
3+3 & 4-2 \\
5+0 & 6+1 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
3 & 2 \\
6 & 2 \\
5 & 7 \\
\end{array} \right]
\end{align}$
Hence, $A+B=\left[ \begin{array}{*{35}{l}}
3 & 2 \\
6 & 2 \\
5 & 7 \\
\end{array} \right]$
(b)
Perform the subtraction of the matrices $A$ and $B$ as below:
$\begin{align}
& A-B=\left[ \begin{array}{*{35}{l}}
1 & 3 \\
3 & 4 \\
5 & 6 \\
\end{array} \right]-\left[ \begin{array}{*{35}{l}}
2 & -1 \\
3 & -2 \\
0 & 1 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
1-2 & 3+1 \\
3-3 & 4+2 \\
5-0 & 6-1 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
-1 & 4 \\
0 & 6 \\
5 & 5 \\
\end{array} \right]
\end{align}$
Hence, $A-B=\left[ \begin{array}{*{35}{l}}
-1 & 4 \\
0 & 6 \\
5 & 5 \\
\end{array} \right]$
(c)
Perform the multiplication of the matrices $A$ with constant number as below:
$\begin{align}
& \left( -4 \right)A=\left( -4 \right)\left[ \begin{array}{*{35}{l}}
1 & 3 \\
3 & 4 \\
5 & 6 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
-4 & -12 \\
-12 & -16 \\
-20 & -24 \\
\end{array} \right]
\end{align}$
Hence, $\left( -4 \right)A=\left[ \begin{array}{*{35}{l}}
-4 & -12 \\
-12 & -16 \\
-20 & -24 \\
\end{array} \right]$
(d)
Perform the multiplication with a content number and addition of the matrices $A$ and $B$ as below:
$\begin{align}
& 3A+2B=3\left[ \begin{array}{*{35}{l}}
1 & 3 \\
3 & 4 \\
5 & 6 \\
\end{array} \right]+2\left[ \begin{array}{*{35}{l}}
2 & -1 \\
3 & -2 \\
0 & 1 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
3 & 9 \\
9 & 12 \\
15 & 18 \\
\end{array} \right]+\left[ \begin{array}{*{35}{l}}
4 & -2 \\
6 & -4 \\
0 & 2 \\
\end{array} \right] \\
& =\left[ \begin{array}{*{35}{l}}
7 & 7 \\
15 & 8 \\
15 & 20 \\
\end{array} \right]
\end{align}$
Hence, $3A+2B=\left[ \begin{array}{*{35}{l}}
7 & 7 \\
15 & 8 \\
15 & 20 \\
\end{array} \right]$