Answer
The solution is, $\underline{x=\frac{-1\pm \sqrt{33}}{4}}$.
Work Step by Step
Consider the given equation,
$\begin{align}
& 2{{x}^{2}}=4-x \\
& 2{{x}^{2}}+x-4=0 \\
& x=\frac{-1\pm \sqrt{{{1}^{2}}-4\left( -4 \right)\left( 2 \right)}}{2\times 2} \\
& =\frac{-1\pm \sqrt{33}}{4}
\end{align}$
The solutions of the equations are $x=\frac{-1\pm \sqrt{33}}{4}$.
