Answer
$(\sqrt 2,\sqrt 2)$
Work Step by Step
Step 1. See plot; move $\theta=\frac{5\pi}{4}$, then $r=-2$ to get the point.
Step 2. Using the formulas $x=r\ cos\theta$ and $y=r\ sin\theta$, we have $x=-2cos\frac{5\pi}{4}=\sqrt 2$ and $y=-2sin\frac{5\pi}{4}=\sqrt 2 $, giving a point $(\sqrt 2,\sqrt 2)$
