Answer
This makes sense.
Work Step by Step
Please note that the function $f(x)=\sin^{-1}x$ is negative for $x \in [-1,0)$ and the function $g(x)=\cos^{-1}x$ is positive for $x \in [-1,1)$.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 628: 118
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