Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 628: 107

Answer

No.

Work Step by Step

We need to consider the domain and range restrictions on $sin^{-1}x$; thus we have $sin^{-1}(sin\frac{5\pi}{6})=sin^{-1}(sin\frac{\pi}{6})=\frac{\pi}{6}$. So the answer is no.
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