Answer
sin θ = $\frac{5}{13}$
cos θ = $\frac{12}{13}$
tan θ =$\frac{5}{12}$
csc θ = $\frac{13}{5}$
sec θ = $\frac{13}{12}$
cot θ = $\frac{12}{5}$
Work Step by Step
$a^{2}$ + $b^{y2}$ = $c^{2}$
given a= 10, c= 26
$10^{2}$ + $b^{2}$ = $26^{2}$
$b^{2}$ = 676- 100
$b^{2}$ = 576
b = $\sqrt {576}$ = 24
sin θ = $\frac{opposite}{hypotenuse}$ = $\frac{10}{26}$ = $\frac{5}{13}$
cos θ = $\frac{adjacent}{hypotenuse}$ = $\frac{24}{26}$ = $\frac{12}{13}$
tan θ = $\frac{opposite}{adjacent}$ = $\frac{10}{24}$ = $\frac{5}{12}$
csc θ = $\frac{1}{sin θ}$ = $\frac{13}{5}$
sec θ = $\frac{1}{cos θ}$ = $\frac{13}{12}$
cot θ = $\frac{1}{tan θ}$ = $\frac{12}{5}$
