Answer
$2b$
Work Step by Step
RECALL:
(1) $\sin{(-t)} = -\sin{t}$
(2) $\cos{(-t)} = \cos{t}$
(3) $\tan{(-t)} = -\tan{t}$
Use the given and rule (2) above to obtain:
$=3\cos{t} -\cos{t}
\\=3b - b
\\=2b$
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