Answer
a.)-$\frac{\sqrt 3}{3}$
b.)$\frac{\sqrt 3}{3}$
Work Step by Step
a.)tan$\frac{11\pi}{6}$ corresponds to $\frac{y}{x}$ value.
tan$\frac{11\pi}{6}$ = $\frac{\frac{-1}{2}}{\frac{\sqrt 3}{2}}$ = -$\frac{\sqrt 3}{3}$
b.)Tangent is an odd function, so tan(-t) = -tant.
tan-$\frac{11\pi}{6}$ = - tan$\frac{11\pi}{6}$ = $\frac{\sqrt 3}{3}$
