Answer
$\sqrt 2$
Work Step by Step
sec(-$\frac{9\pi}{4}$) = sec $\frac{9\pi}{4}$
sec($\frac{\pi}{4}$ + 2$\pi$) = sec$\frac{\pi}{4}$
sec $\frac{\pi}{4}$=$\frac{1}{cos \frac{\pi}{4}}$
sec $\frac{\pi}{4}$ =$\frac{1}{\frac{\sqrt 2}{2}}$ = $\sqrt 2$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 42
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