Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Cumulative Review Exercises - Page 647: 9

Answer

$3$

Work Step by Step

$ \log 25 +\log 40 = \log (40 \cdot 25 )$ or, $=\log (1000)$ or, $= \log 10^3$ or, $3 \log 10 = 3 \times 1 =3$
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