Answer
$-5,-2,2$
Work Step by Step
Re-arrange as: $ x^3+5x^2-4x-20=0$
$\implies x^2(x+5)-4(x+5)=0$
$\implies (x+5)(x^2-4)=0$
or, $(x+5)(x-2)(x+2)=0$
So, $ x=-5,-2,2$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Cumulative Review Exercises - Page 647: 2
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