Answer
$ x \in [-3,8]$
Work Step by Step
$-11 \leq 2x-5 \leq 11$
or, $-11+5 \leq 2x-5+5 \leq 11+5$
or, $-6 \leq 2x \leq 16$
So, $-3 \leq x \leq 8$
So, $ x \in [-3,8]$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Cumulative Review Exercises - Page 647: 6
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