Answer
$ f^{-1} (x)= x^2+6$
Work Step by Step
Re-arrange as: $ y=\sqrt {x-6}$
$ y^2=(\sqrt {x-6})^2$
or, $ y^2=x-6$
or, $ x=y^2+6$
So, $ f^{-1} (x)= x^2+6$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Cumulative Review Exercises - Page 647: 7
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