Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.1 - Exponential Functions - Exercise Set - Page 451: 90

Answer

The statement is true.

Work Step by Step

Applying the rules $\qquad a^{-n}=\displaystyle \frac{1}{a^{n}},\ (\displaystyle \frac{a}{b})^{n}=\frac{a^{n}}{b^{n}}$ it follows that $3^{-x}=(\displaystyle \frac{1}{3})^{x}$, so $ f(x)=g(x).$ The statement is true.
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