Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.1 - Exponential Functions - Exercise Set - Page 451: 85

Answer

Does not make sense.

Work Step by Step

If a linear model is appropriate, the slopes on various intervals should be close, if not equal. Slope between 1945 and 1974: $ m_{1}=\displaystyle \frac{19500-8200}{1974-1945}=\frac{11300}{29}\approx 390$ Slope between 1974 and 1993: $ m_{2}=\displaystyle \frac{40500-19500}{1993-1974}=\frac{21000}{19}\approx 1105$ Slope between 1993 and 2013: $ m_{3}=\displaystyle \frac{73950-40500}{2013-1993}=\frac{33450}{20}\approx 1670$ So, as time passes, the slope rises. This suggests an exponential model rather than a linear one. Does not make sense.
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