Answer
The correct option is (b).
Work Step by Step
Consider the polynomial function:
$f\left( x \right)=-{{x}^{4}}+{{x}^{2}}$
The degree is $n=4$ and the leading coefficient is $-1$
The Leading Coefficient Test: Consider the polynomial function, $f\left( x \right)={{a}_{n}}{{x}^{n}}+{{a}_{n-1}}{{x}^{n-1}}+...+{{a}_{1}}x+{{a}_{0}}\left( {{a}_{n}}\ne 0 \right)$ -- the leading coefficient is ${{a}_{n}}$.
That is, the odd-degree polynomial function has graphs with opposite behavior at each end while even-degree polynomial shows the same behavior at each end.
The degree of the given function is $n=4$, which is even.
Now consider the leading coefficient of the polynomial function:
$\begin{align}
& {{a}_{4}}=-1 \\
& <0
\end{align}$
Therefore, from the Leading Coefficient Test, the graph falls to the left and falls to the right. That is different behavior at each end.
