Answer
quotient $3x^3-4x^2+7$, remainder $0$
Work Step by Step
Step 1. Using synthetic division as shown in the figure, we have $\frac{3x^4+11x^3-20x^2+7x+35}{x+5}=3x^3-4x^2+7+\frac{0}{x+5}$
Step 2. We can identify the quotient as $3x^3-4x^2+7$ and the remainder as $0$
