Answer
See graph and explanations.
Work Step by Step
Step 1. Given the function $f(x)=2x^2(x-1)^3(x+2)$, we can identify the zeros and their multiplicities as $x=0$ (multiplicity 2), $x=1$ (multiplicity 3), $x=-2$ (multiplicity 1).
Step 2. The curve will cross the x-axis at $x=1$ and $x=-2$, but will touch and turn around at $x=0$
Step 3. The leading term is $2x^6$ with a coefficient of $+2$ and an even power. Thus, we can identify its end behaviors as $x\to-\infty, y\to\infty$ and $x\to\infty, y\to\infty$. That is, the curve rises to the left and also rises to the right.
Step 4. We test
$f(-x)=2(-x)^2(-x-1)^3(-x+2)=2x^2(x+1)^3(x-2)$
as $f(-x)\ne f(x)$ and $f(-x)\ne -f(x)$, the function is neither symmetric with respect to the y-axis nor with the origin.
Step 5. Let $x=0$; we can find the y-intercept as $y=0$
Step 6. Based on the above results, we can graph the function as shown in the figure.
