Answer
$0,3$
Work Step by Step
$(f o g) (x)=\dfrac{2}{3/x-1}=\dfrac{2(x-1)}{3}$
Now, $\lim_\limits{x \to 1} (f o g) (x)=\dfrac{2(1-1)}{3}=0$
and $( g o f) (x)=\dfrac{3}{2/x-1}=\dfrac{3x}{2-x}$
Now, $\lim_\limits{x \to 1} ( g o f) (x)=\dfrac{3(1)}{2-1}=3$
Answers: $0,3$
