Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.2 - Finding Limits Using Properties of Limits - Exercise Set - Page 1153: 17

Answer

$\dfrac{5}{6}$

Work Step by Step

Recall that if $ f $ is a polynomial function, then we have $\lim_\limits{x\to a}f(x)=f(a)$. In order to to find the limit, we will plug $ a $ into the function and then simplify. $\lim_\limits{x\to 5} \dfrac{x}{x+1}=\dfrac{\lim_\limits{x\to 5} x}{\lim_\limits{x\to 5} (x+1)}=\dfrac{5}{6}$
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