Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Review Exercises - Page 1179: 24

Answer

$6$

Work Step by Step

Recall that if $ f $ is a polynomial function, then we have $\lim_\limits{x\to a}f(x)=f(a)$. In order to to find the limit, we will plug $ a $ into the function and then simplify. $\lim_\limits{x\to 3} \dfrac{x^2-9}{x-3}=\lim_\limits{x\to 3} \dfrac{(x-3)(x+3)}{x-3}$ or, $= \lim_\limits{x\to 3}(x+3)$ or, $=6$
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