Answer
point-slope form: $y+7=-2(x-4)$
general form: $2x+y-1=0$
Work Step by Step
Step 1. As the line is perpendicular to the line $x-2y-3=0$, we have its slope $m=-2$
Step 2. As the line passes through the point $(4,-7)$, we can write the line equation in point-slope form as $y+7=-2(x-4)$
Step 3. The above equation can be rewritten in general form as $y+7=-2x+8$ or $2x+y-1=0$
