Answer
point-slope form: $y-3=\frac{3}{2}(x+1)$
general form: $3x-2y+9=0$
Work Step by Step
Step 1. As the line is parallel to the line $3x-2y-5=0$, we have its slope $m=\frac{3}{2}$
Step 2. As the line passes through the point $(-1,3)$, we can write the line equation in point-slope form as $y-3=\frac{3}{2}(x+1)$
Step 3. The above equation can be rewritten in general form as $2y-6=3x+3$ or $3x-2y+9=0$
