Answer
(a) $\frac{9}{4}$, $(-1,\frac{9}{4})$.
(b) $3$, $(3,66)$.
Work Step by Step
(a) Given $g(x)=4^x+2$, we have $g(-1)=4^{-1}+2=\frac{9}{4}$ which gives a point $(-1,\frac{9}{4})$.
(b) For $g(x)=66$, we have $4^x+2=66$, which gives $4^x=64=4^3$ or $x=3$ and a point $(3,66)$.
