Answer
(a) $16$, $(4,16)$.
(b) $-4$, $(-4,\frac{1}{16})$.
Work Step by Step
(a) Given $f(x)=2^x$, we have $f(4)=2^4=16$ which gives a point $(4,16)$.
(b) For $f(x)=\frac{1}{16}=2^{-4}$, we have $2^x=2^{-4}$, which gives $x=-4$ and a point $(-4,\frac{1}{16})$.
