Answer
$\approx 0$
Work Step by Step
We have to determine the limit:
$\displaystyle\lim_{x\rightarrow -1} \dfrac{x^3+2x^2+x}{x^4+x^3+2x+2}$
We use a graphing utility to compute the limit.
The result is:
$\displaystyle\lim_{x\rightarrow -1} \dfrac{x^3+2x^2+x}{x^4+x^3+2x+2}\approx 0$
