Answer
$\approx 0.80$
Work Step by Step
We have to determine the limit:
$\displaystyle\lim_{x\rightarrow 1} \dfrac{x^3-x^2+3x-3}{x^2+3x-4}$
We use a graphing utility to compute the limit.
The result is:
$\displaystyle\lim_{x\rightarrow 1} \dfrac{x^3-x^2+3x-3}{x^2+3x-4}\approx 0.80$
