Answer
$\approx 1.60$
Work Step by Step
We have to determine the limit:
$\displaystyle\lim_{x\rightarrow 2} \dfrac{x^3-2x^2+4x-8}{x^2+x-6}$
We use a graphing utility to compute the limit.
The result is:
$\displaystyle\lim_{x\rightarrow 2} \dfrac{x^3-2x^2+4x-8}{x^2+x-6}\approx 1.60$