Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 7 - Algebra: Graphs, Functions, and Linear Systems - Chapter Summary, Review, and Test - Review Exercises - Page 481: 45

Answer

\[\left\{ \left( 3,-1 \right) \right\}\]

Work Step by Step

Multiply the first equation by 5 and add both the equations as follows: \[\begin{align} & 15x+5y+2x-5y=40+11 \\ & 17x=51 \\ & x=\frac{51}{17} \\ & x=3 \end{align}\] Substitute the value of \[x=3\]in the first equation and solve \[\begin{align} & 3x+y=8 \\ & 3\left( 3 \right)+y=8 \\ & y=8-9 \\ & y=-1 \end{align}\] Hence, the value of x is 3 and y is −1.
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