Answer
\[\left\{ \left( 2,-3 \right) \right\}\]
Work Step by Step
Multiply the first equation by 4 and the second equation by −3 then add both the equations as follows:
\[\begin{align}
& 20x+12y-9x-12y=4+18 \\
& 11x=22 \\
& x=\frac{22}{11} \\
& x=2
\end{align}\]
Substitute the value of \[x=2\]in the first equation and solve
\[\begin{align}
& 5x+3y=1 \\
& 5\left( 2 \right)+3y=1 \\
& y=\frac{1-10}{3} \\
& y=-3
\end{align}\]
Hence, the value of x is 2 and y is −3.
