Answer
\[\left\{ \left( 3,4 \right) \right\}\]
Work Step by Step
Multiply the first equation by 2 and add both the equations as follows:
\[\begin{align}
& 4x-2y+x+2y=4+11 \\
& 5x=15 \\
& x=\frac{15}{5} \\
& x=3
\end{align}\]
Substitute the value of \[x=3\]in the second equation and solve
\[\begin{align}
& x+2y=11 \\
& 3+2y=11 \\
& y=\frac{11-3}{2} \\
& y=4
\end{align}\]
Hence, the value of x is 3 and y is 4.
