Answer
\[\varnothing \]
Work Step by Step
Observing the system, a method of substitution becomes appropriate.
Let equation 1 be \[y=-x+4\] and equation 2 be \[3x+3y=-6\]
Substitute equation 1 in equation 2 for y, equation 2 becomes,
\[\begin{align}
& 3x+3\left( -x+4 \right)=-6 \\
& 3x-3x+12=-6 \\
& 12=-6
\end{align}\]
Both variables are eliminated and the statement is false. So, the system has no solution.
