Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - Chapter Summary, Review, and Test - Review Exercises - Page 403: 17

Answer

\[x=\frac{2}{5}\]

Work Step by Step

\[\frac{x+2}{3}=\frac{4}{5}\] The LCM is\[15\] so multiply both the sides by \[15\] \[\frac{x+2}{3}\times 15=\frac{4}{5}\times 15\] This gives, \[5\left( x+2 \right)=12\] Apply the distributive law \[5x+10=12\] Or, \[5x=2\] Divide both the sides by \[5\] \[x=\frac{2}{5}\] Now, to check it, put \[x=\frac{2}{5}\]in the equation \[\begin{align} & \frac{x+2}{3}=\frac{4}{5} \\ & \frac{\frac{2}{5}+2}{3}=\frac{4}{5} \\ & \frac{12}{15}=\frac{4}{5} \\ & \frac{4}{5}=\frac{4}{5} \\ \end{align}\] which is true. The required solution is\[x=\frac{2}{5}\].
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