Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - Chapter Summary, Review, and Test - Review Exercises - Page 403: 16

Answer

\[x=-65\]

Work Step by Step

Consider the equation \[\frac{-7}{5}=\frac{91}{x}\] The LCM is\[5x\] so multiply both the sides by \[5x\] \[\frac{-7}{5}\times 5x=\frac{91}{x}\times 5x\] This gives, \[-7x=455\] Divide both the sides by \[-7\] \[\begin{align} & x=-\frac{455}{7} \\ & =-65 \end{align}\] That is, \[x=-65\] Now, to check it, put \[x=-65\]in the equation \[\begin{align} & \frac{-7}{5}=\frac{91}{x} \\ & \frac{-7}{5}=\frac{91}{-65} \\ & \frac{-7}{5}=\frac{-7}{5} \end{align}\] which is true. The required solution is\[x=-65\].
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