Answer
(x+1)(x+16)
Work Step by Step
$x^{2}$ + 17x+16
step 1. Enter x as the first term of each factor
$x^{2}$ + 17x + 16= (x__)(x _)
Step 2. To find the second term of each factor, we must find two integers whose product is 16 and whose sum is 17
List pairs of factors of the constant, 16
(1,16)(2,8)(4,4)
step 3. The correct factorization of $x^{2}$ +17x +16 is the one in which the sum of the Outside and Inside products is equal to 17x
So (1,16) satisfy the condition
$x^{2}$ + 17x + 16 = $x^{2}$ +1x+16x + 16 = (x+1)(x+16)
