Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 337: 148

Answer

shown below

Work Step by Step

(a) Consider the given data: \[\begin{align} & \frac{16.24}{15.98}=1.02 \\ & \frac{16.50}{16.24}=1.02 \\ & \frac{16.76}{16.50}=1.02 \\ & \frac{17.03}{16.76}=1.02 \\ \end{align}\] \[\begin{align} & \frac{17.30}{17.03}=1.02 \\ & \frac{17.58}{17.30}=1.02 \\ & \frac{17.86}{17.58}=1.02 \\ & \frac{18.15}{17.86}=1.02 \\ \end{align}\] \[\begin{align} & \frac{18.44}{18.15}=1.02 \\ & \frac{18.80}{18.44}=1.02 \\ \end{align}\] Take the geometric mean of the above outputs: \[\frac{1.02+1.02+1.02+1.02+1.02+1.02+1.02+1.02+1.02+1.02}{10}=1.02\] It is shown that the increase in the population of Florida is approximately geometric. (b) The general model for n successions is given by: \[{{a}_{n}}=a{{\left( r \right)}^{n-1}}\] Where, β€˜a’is the first term of the series, r is the common geometric ratio between the terms and n is the number of terms. (c) The mathematical model created in the previous part is given as: \[{{a}_{n}}=15.98{{\left( 1.02 \right)}^{n-1}}\] By using the above formula for: \[\begin{align} & n=2030-2000 \\ & n=30, \\ & {{a}_{n}}=15.98{{\left( 1.02 \right)}^{30-1}} \\ & {{a}_{n}}=15.98{{\left( 1.02 \right)}^{29}} \end{align}\] \[\begin{align} & {{a}_{n}}=15.98\left( 1.77 \right) \\ & {{a}_{n}}=28.38\text{ million} \\ \end{align}\]
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