Answer
\[\frac{1}{2}\]
Work Step by Step
To find the sixth term put \[n=6\] in the above formula, to get:
\[\begin{align}
& {{a}_{6}}={{a}_{1}}{{r}^{6-1}} \\
& =16\cdot {{\left( \frac{1}{2} \right)}^{5}} \\
& =16\cdot \frac{1}{32} \\
& =\frac{1}{2}
\end{align}\]
The sixth term of the geometric sequence is\[\frac{1}{2}\].
