Answer
$\dfrac{1}{9}$
Work Step by Step
(i) $a^m \cdot a^n = a^{m+n}$
(ii) $\dfrac{a^m}{a^n}=a^{m-n}, a \ne 0$
Use rule (i) to find:
$=3^{-3+1}
\\=3^{-2}$
Use rule (ii) to find:
$=\dfrac{1}{3^2}
\\=\dfrac{1}{9}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.