Answer
$\frac{1}{9}$
Work Step by Step
(i) $a^{-m} =\dfrac{1}{a^m}, a \ne 0, m \gt 0$
Use rule (i) to find:
$3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}$
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 5 - Number Theory and the Real Number System - 5.6 Exponents and Scientific Notation - Exercise Set 5.6 - Page 320: 20
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