Answer
$\dfrac{1}{32}$
Work Step by Step
(i) $a^{-m} =\dfrac{1}{a^m}, a \ne 0, m \gt 0$
Use rule (i) to find:
$2^{-5}=\dfrac{1}{2^5}\\\dfrac{1}{2*2*2*2*2}\\\dfrac{1}{32}$
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