Answer
330
Work Step by Step
The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
11C4 = $\frac{11!}{4!(11-4)!}$
=$\frac{11!}{4!7!}$
=$\frac{11*10*9*8*7!}{4!7!}$
==$\frac{11*10*9*8}{4*3*2*1}$
=330
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 11 - Counting Methods and Probability Theory - 11.3 Combinations - Exercise Set 11.3 - Page 707: 9
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