Answer
1
Work Step by Step
The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
7C7 = $\frac{7!}{7!(7-7)!}$
=$\frac{7!}{7!0!}$
0!=1, so the answer is 1.
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 11 - Counting Methods and Probability Theory - 11.3 Combinations - Exercise Set 11.3 - Page 707: 13
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