Answer
210
Work Step by Step
The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
10C6 = $\frac{10!}{6!(10-6)!}$
=$\frac{10!}{6!4!}$
=$\frac{10*9*8*7*6!}{6!4!}$
=$\frac{10*9*8*7}{4*3*2*1}$ = 210
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 11 - Counting Methods and Probability Theory - 11.3 Combinations - Exercise Set 11.3 - Page 707: 8
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