Answer
$\alpha\approx44^{\circ}$
$\beta\approx46^{\circ}$
Work Step by Step
$\sin\alpha=\frac{14}{20}$
$\alpha=\sin^{-1}\frac{14}{20}$
$\alpha\approx44^{\circ}$
Sum of interior angles of a triangle $= 180^{\circ}$
$90^{\circ} + \alpha + \beta = 180^{\circ}$
$90^{\circ} + 44^{\circ} + \beta \approx 180^{\circ}$
$\beta\approx46^{\circ}$
