Answer
Convergent
Work Step by Step
Since, we have $\lim\limits_{x \to \infty} \int_1^\infty\sec h^2 x dx$
or, $=\lim\limits_{a \to \infty} \tan h x|_{1}^{a}$
or, $ = \lim\limits_{a \to \infty}(\tanh a-tanh 1)$
or, $=1- tanh 1$
or, $\approx 0.76$
Hence, the series is Convergent
