Answer
Diverges
Work Step by Step
Since, we have $\Sigma_{n=1}^\infty \dfrac{-8}{n}=-8\Sigma_{n=1}^\infty \dfrac{1}{n}$
Here, the given series is a harmonic series with partial sums not bounded.
and, since $\Sigma_{n=1}^\infty \dfrac{1}{n}$ diverges, so does our sum.
Hence, the given series diverges.
