Answer
Converges
Work Step by Step
Since, the given series is a geometric series with common ratio $r=\dfrac{1}{\ln 3}$
Thus, for this series $|r|=\dfrac{1}{\ln 3} \approx 0.91 \lt 1$
Hence, the given series Converges.
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 9 - Section 9.3 - The Integral Test - Exercises - Page 504: 30
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